Which of the following is the minimum value of the equation y = 2×2 + 5? 5 0 −5 <

Question

Which of the following is the minimum value of the equation y = 2×2 + 5?

5

0

−5

2

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Minh Khuê 5 months 2021-08-11T10:15:30+00:00 1 Answers 3 views 0

Answers ( )

    0
    2021-08-11T10:16:48+00:00

    (0, 5) is the minimum value.

    Find the axis of symmetry by plugging the respective variables into -b/2a

    -5/2(0) = 0

    There is no b-value in our equation, or rather, the value of b is 0. To see this, y = 2x^2 + 5 can be written as

    y = 2x^2 + 0x + 5

    We plug 0 into f(x), establishing every x-value as 0.

    f(0) = 2(0)^2 + 5
    f(0) = 0 + 5
    f(0) = 5

    5 is now your vertex’s y-value. Plot the two values together.

    (0, 5)

    We know that this is a minimum because the leading coefficient is positive, meaning the the graph’s parabola will open down.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )