which equation models the same quadratic relationship as function f? f(x)=x^2+12x+4 a) y=(x-6)^2+40 b) y=(x+6)^2-32 c) y=(x-6)^2-32 d) y=(x+

Question

which equation models the same quadratic relationship as function f? f(x)=x^2+12x+4 a) y=(x-6)^2+40 b) y=(x+6)^2-32 c) y=(x-6)^2-32 d) y=(x+6)^2+40​

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Euphemia 4 years 2021-08-07T18:31:41+00:00 2 Answers 11 views 0

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    0
    2021-08-07T18:33:12+00:00

    9514 1404 393

    Answer:

      b) y=(x+6)^2-32

    Step-by-step explanation:

    Add and subtract the square of half the x-coefficient to put into vertex form.

      f(x) = x^2 +12x +4 . . . . . given

      y = x^2 +12x +36 +4 -36 . . . . add and subtract (12/2)^2 = 36

      y = (x +6)^2 -32 . . . . . . . . . . . write in vertex form

    0
    2021-08-07T18:33:18+00:00

    Answer:

    B. Y=(x+6)²-32

    Step-by-step explanation:

    hope it helps

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