When responding to sound, the human eardrum vibrates about its equilibrium position. Suppose an eardrum is vibrating with an amplitude of 7.

Question

When responding to sound, the human eardrum vibrates about its equilibrium position. Suppose an eardrum is vibrating with an amplitude of 7.5 x10-7 m and a maximum speed of 3.3 x10-3 m/s. (a) What is the frequency (in Hz) of the eardrum’s vibrations

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Minh Khuê 4 years 2021-07-27T23:58:37+00:00 1 Answers 6 views 0

Answers ( )

  1. Adela
    0
    2021-07-28T00:00:30+00:00
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    Answer:

    f = 700 Hz

    Explanation:

    given

    amplitude =a= 7.5 \times 10^{-7} m

    speed v =3.3 \times 10^{-3} m/s

    for (a)

    we know v_{max} = a\omega

    and \omega = 2\pi f

    we get

    v_{max} = a( 2 \pi f)

    f = \frac{v_{max}}{2 \pi a}

    f = \frac{ 3.3 \times 10^{-3}}{ 2 \times 3.14 \times 7.5 \times 10^{-7}}

    f = 700 Hz

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