When a mass is suspended from a spring the latter extends over a distance of 10cm. What will be the period of oscillations of the same syste

Question

When a mass is suspended from a spring the latter extends over a distance of 10cm. What will be the period of oscillations of the same system if it is placed horizontal on a frictionless surface​

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Huyền Thanh 3 years 2021-08-19T10:29:14+00:00 1 Answers 10 views 0

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  1. RobertKer
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    2021-08-19T10:30:47+00:00
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    Answer:

    0.64 s

    Explanation:

    It’s period of oscillation (T) can be determined by,

    T = 2\pi[tex]\sqrt{\frac{l}{g} }[/tex]

    Where l is the length (extension on the spring), and g the acceleration due to gravity.

    But,

    l = 10 cm = 0.1 m

    g = 9.8 m/s^{2}

    Thus,

    T = 2 x \frac{22}{7} \sqrt{\frac{0.1}{9.8} }

      = 0.6350

    T = 0.64 s

    The period of oscillation would be 0.64 s.

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