When a light bulb is connected to a 4.5 V battery, a current of 0.16 A passes through the bulb filament. What is the resistance of the filam

Question

When a light bulb is connected to a 4.5 V battery, a current of 0.16 A passes through the bulb filament. What is the resistance of the filament

in progress 0
Eirian 3 months 2021-07-30T17:35:38+00:00 1 Answers 13 views 0

Answers ( )

    0
    2021-07-30T17:36:59+00:00

    Answer:

    R = 28.125 ohms

    Explanation:

    Given that,

    The voltage of a bulb, V = 4.5 V

    Current, I = 0.16 A

    We need to find the resistance of the filament. Using Ohm’s law,

    V = IR

    Where

    R is the resistance of the filament

    So,

    R=\dfrac{V}{I}\\\\R=\dfrac{4.5}{0.16}\\\\R=28.125\ \Omega

    So, the resistance of the filament is equal to 28.125 ohms.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )