When a golfer tees off, the head of her golf club which has a mass of 151 g is traveling 43.9 m/s just before it strikes a 46.0 g golf ball

Question

When a golfer tees off, the head of her golf club which has a mass of 151 g is traveling 43.9 m/s just before it strikes a 46.0 g golf ball at rest on a tee. Immediately after the collision, the club head continues to travel in the same direction but at a reduced speed of 28.2 m/s. Neglect the mass of the club handle and determine the speed of the golf ball just after impact

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Neala 4 years 2021-07-18T22:21:45+00:00 1 Answers 22 views 0

Answers ( )

  1. dangkhoa
    0
    2021-07-18T22:23:27+00:00
    Reply

    Answer:

    51.54 m/s

    Explanation:

    Applying,

    Law of conservation of momentum,

    Total momentum before collision = Total momentum after collision

    mu+m’u’ = mv+m’v’……………….. Equation 1

    Where m = mass of the head of the golf club, m’ = mass of the gulf ball, u = initial velocity of the head of the gulf club, u’ = initial velocity of the gulf ball, v = final velocity of the head of a gulf club, v’ = final velocity of the gulf ball

    From the question,

    Given: m = 151 g = 0.151 kg, u = 43.9 m/s, m’ = 46 g = 0.046 kg, u’ = 0 m/s (at rest), v = 28.2 m/s

    Substitute these values into equation 1

    0.151(43.9)+0.046(0) = 0.151(28.2)+0.046(v’)

    solve for v’

    6.6289+0 = 4.2582+0.046v’

    0.046v’ = 6.6289-4.2582

    0.046v’ = 2.3707

    v’ = 2.3707/0.046

    v’ = 51.54 m/s

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