When 28242 J are transferred to water sample, its temperature increases 18⁰C to 63⁰C. Determine the mass of the water sample.

Question

When 28242 J are transferred to water sample, its temperature increases 18⁰C to 63⁰C. Determine the mass of the water sample.

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Yến Oanh 4 years 2021-08-28T11:17:29+00:00 1 Answers 23 views 0

Answers ( )

  1. thienan
    0
    2021-08-28T11:18:30+00:00
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    Answer:

    149.79

    Explanation:

    Formula

    Joules = m * c * delta (t)

    Givens

    J = 28242

    m = ?

    c = 4.19

    Δt = 63 – 18 = 45

    Solution

    28242 = m * 4.19 * 45

    28242 = m * 188.55

    m = 28242 / 188.55

    m = 149.79

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