What will the surface charge density be if the radius of the disk is doubled but its total charge remains the same

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What will the surface charge density be if the radius of the disk is doubled but its total charge remains the same

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Thu Giang 1 year 2021-08-15T03:22:56+00:00 1 Answers 52 views 0

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    2021-08-15T03:24:14+00:00

    Answer:

    the new surface charge density = Q/4πr²( initial surface charge density divided by 4)

    Explanation:

    charge density(surface) = Q/A = charge/area

    let r be the initial radius of the disk

    therefore, area A = πr²

    charge density = Q/πr²

    Now that the radius is doubled, let it be represented as R

    ∴ R = 2r

    Recall, charge density = Q/A

    A = πR = π(2r)² = 4πr²

    the new surface charge density = Q/4πr²

    the initial surface charge density divided by 4

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