What will happen to the force felt between two charged objects if the distance between them is 1/3rd of the original distance

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What will happen to the force felt between two charged objects if the distance between them is 1/3rd of the original distance

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Thành Đạt 4 years 2021-08-18T22:19:02+00:00 1 Answers 7 views 0

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    2021-08-18T22:20:27+00:00

    Answer:

    New force = 9(initial force)

    Explanation:

    The force between two charges is given by :

    F=\dfrac{kq_1q_2}{r^2}

    Where

    d is the original distance

    Let d’ is the new distance such that, r’ = r/3

    New force,

    F'=\dfrac{kq_1q_2}{r'^2}\\\\F'=\dfrac{kq_1q_2}{(\dfrac{r}{3})^2}\\\\F'=9\times \dfrac{kq_1q_2}{r^2}\\\\F'=9F

    So, the new force becomes 9 times the initial force.

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