What volume is occupied by 0.104 mol of helium gas at a pressure of 0.91 atm and a temperature of 314 K ?

Question

What volume is occupied by 0.104 mol of helium gas at a pressure of 0.91 atm and a temperature of 314 K ?

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Adela 2 months 2021-07-12T02:33:16+00:00 1 Answers 2 views 0

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    2021-07-12T02:34:44+00:00

    Answer:

    The volume will be “2.95 L“.

    Explanation:

    Given:

    n = 0.104

    p = 0.91 atm

    T = 314 K

    Now,

    The Volume (V) will be:

    = \frac{nRT}{P}

    By putting the values, we get

    = \frac{0.104\times 0.0821\times 314}{0.91}

    = \frac{2.6810}{0.91}

    = 2.95 \ L

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