What quantity of electricity will liberate 0.125 more of oxygen molecules during the electrolysis of dilute sodium chlor

Question

What quantity of electricity
will liberate 0.125 more
of oxygen molecules during
the electrolysis of dilute
sodium chloride solution (f=
96500cmol)​

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Khánh Gia 4 weeks 2021-08-17T16:14:09+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-08-17T16:15:28+00:00

    Answer:

    96500 C

    Explanation:

    The equation of the electrolytic process is;

    4OH^-(aq) —–> 2H2O(l) +O2(g) + 4e

    From the reaction equation; one mole of oxygen is liberated by 4 moles of electrons.

    If one mole of electrons= 96500 Cmol-1, then;

    1 mole of oxygen is liberated by 4×96500 Cmol-1

    0.25 moles of oxygen will be liberated by 0.25 × 4×96500/1 = 96500 C

    Therefore, 0.25 moles of oxygen is liberated by 96500 C

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