What percentage of the original activity in the sample remains after 17.5 days? half life calculation

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What percentage of the original activity in the sample remains after 17.5 days? half life calculation

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Delwyn 1 month 2022-12-24T07:26:52+00:00 1 Answer 0 views 0

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    2022-12-24T07:27:55+00:00
    The percentage of the original activity in the sample remains after 17.5 days is obtained as N(t) / No x 100%.

    What is half life?

    Half-life is the time required for a quantity to reduce to half of its initial value.
    The original activity in the sample that remains after 17.5 days is calculated from half life equation as shown below;
    N(t) = No(¹/₂)^t/h
    where;
    • N(t) is the mass of the substance remaining
    • No is the initial mass of the substance
    • t is time elapsed = 17.5 days
    • h is the half life of the substance
    percentage of the original activity in the sample remains after 17.5 days;
    = N(t) / No x 100%
    Thus, the percentage of the original activity in the sample remains after 17.5 days is obtained as N(t) / No x 100%.
    Learn more about half life here: https://brainly.com/question/2320811
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