What mass of methane (in g) must be burned in order to liberate 12567 kJ of heat?

Question

What mass of methane (in g) must be burned in order to liberate 12567 kJ of heat?

in progress 0
Orla Orla 3 months 2021-08-09T12:43:50+00:00 1 Answers 37 views 0

Answers ( )

    0
    2021-08-09T12:45:34+00:00

    Answer:

    Mass of methane required in gram = 226.35 gram (Approx.)

    Explanation:

    Given:

    Heat energy used = 12,567 kJ

    Missing data;

    Δcombustion = 891  kJ/mol

    Find:

    Mass of methane required in gram

    Computation:

    Number of mol methane burned = Heat energy used / Δcombustion

    Number of mol methane burned = 12,571 / 891

    Number of mol methane burned = 14.1088 mol

    1 mol of methane in gram = 16.043 grams

    So,

    Mass of methane required in gram = Number of mol methane burned x 1 mol of methane in gram

    Mass of methane required in gram = 14.1088 x 16.043

    Mass of methane required in gram = 226.3474

    Mass of methane required in gram = 226.35 gram (Approx.)

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )