What is the volume of 3.00 M sulfuric aid that contain 9.809 g of H2SO4 (98.09g/mol)

Question

What is the volume of 3.00 M sulfuric aid that contain 9.809 g of H2SO4 (98.09g/mol)

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Gerda 3 months 2021-08-18T06:39:17+00:00 1 Answers 1 views 0

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    2021-08-18T06:40:44+00:00

    Given :

    Molarity of sulfuric acid solution is 3.0 M.

    Amount of sulfuric acid present in solution is 9.809 g.

    To Find :

    The volume of solution.

    Solution :

    We know, molarity is given by :

    Molarity = \dfrac{number \ of \ moles \times 1000}{Volume\ ( ml )}\\\\M = \dfrac{w \times 1000}{M.M \times V}\\\\3 = \dfrac{9.809\times 1000}{98.09 \times V}\\\\V = \dfrac{1000}{10\times 3}\  ml\\\\V = 33.33 \ ml

    Therefore, volume required is 33.33 ml .

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