What is the value of z in the equation 2(4z − 3 − 1) = 166 − 46? I know that 166-46 is 120 but i get stuck on the distributive propert

Question

What is the value of z in the equation 2(4z − 3 − 1) = 166 − 46?
I know that 166-46 is 120 but i get stuck on the distributive property part. I end up with 8z-2. Also I will give brainliest.

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Thu Nguyệt 3 days 2021-07-19T16:42:15+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-07-19T16:44:00+00:00

    Answer:

    Step-by-step explanation:

    you have to multiply 2(4z – 3 – 1 ). so 2 * 4z = 8z. so then you would do 2 * (-3) = -6. then you would do the same with -1. 2* (-1) = -2.

    now you have to put it back in equation form. 8z – 6 – 2 = 166 – 46. now you have to combine like terms. -6-2 = -8. 166 – 46 = 120. and then put it back into equation form. 8z – 8 = 120. then you add 8 to 120. 120+8 = 128. now to find z all you have to do is divide 128/8 = 16

    z = 16  

    0
    2021-07-19T16:44:05+00:00

    Answer:

    2(4z − 3 − 1) = 166 − 46

    8z − 6 − 2 = 120

    8z − 8 = 120

    8z = 128

    z = 16

    pls give the brainliest

    Step-by-step explanation:

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )