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## What is the value of z in the equation 2(4z − 3 − 1) = 166 − 46? I know that 166-46 is 120 but i get stuck on the distributive propert

Question

What is the value of z in the equation 2(4z − 3 − 1) = 166 − 46?

I know that 166-46 is 120 but i get stuck on the distributive property part. I end up with 8z-2. Also I will give brainliest.

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Mathematics
3 years
2021-07-19T16:42:15+00:00
2021-07-19T16:42:15+00:00 2 Answers
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## Answers ( )

Answer:Step-by-step explanation:you have to multiply 2(4z – 3 – 1 ). so 2 * 4z = 8z. so then you would do 2 * (-3) = -6. then you would do the same with -1. 2* (-1) = -2.

now you have to put it back in equation form. 8z – 6 – 2 = 166 – 46. now you have to combine like terms. -6-2 = -8. 166 – 46 = 120. and then put it back into equation form. 8z – 8 = 120. then you add 8 to 120. 120+8 = 128. now to find z all you have to do is divide 128/8 = 16

z = 16

Answer:2(4z − 3 − 1) = 166 − 46

8z − 6 − 2 = 120

8z − 8 = 120

8z = 128

z = 16

pls give the brainliest

Step-by-step explanation: