what is the value of the expression? when y=6 and z=2
3y−z/y+5z
a 1
b 3
c 4
d 16
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Given:
y = 6
z = 2
To find:
value of expression 3y – z/y + 5z or (3y-z)/(y+5z)
Steps:
substituting the values we get,
3(6)-2/6 + 5(2)
= 18 – 1/3 + 10
= 27 + 2/3
since thats not there in the options i will try the 2nd one, (next time when writing question pls put brackets to signify if we to divide 2 numbers by and number
Given:
y = 6
z = 2
To find:
value of expression 3y – z/y + 5z or (3y-z)/(y+5z)
Steps:
substituting the values we get,
3(6)-2/6 + 5(2)
= 18 – 1/3 + 10
= 27 + 2/3
since thats not there in the options i will try the 2nd one, (next time when writing question pls put brackets to signify if we to divide 2 numbers by and number
[tex]\frac{3(6)-2}{6+5(2)}[/tex]
[tex]=\frac{18 – 2}{6 + 10}[/tex]
[tex]= \frac{16}{16}[/tex]
[tex]= 1[/tex]
Therefore, the answer is option A) 1
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