What is the value of delta G at 292 for a reaction in which deltaH = 92 kj/mol and delta S= 2.38 kj/mol K

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What is the value of delta G at 292 for a reaction in which deltaH = 92 kj/mol and delta S= 2.38 kj/mol K

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RI SƠ 6 months 2021-08-10T05:45:02+00:00 1 Answers 3 views 0

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    2021-08-10T05:46:23+00:00

    Answer: The value of \Delta G is -602.96 kJ/mol at 292 k for a reaction in which \Delta H = 92 kj/mol and \Delta S = 2.38 kj/mol K.

    Explanation:

    Given: Temperature = 292 K

    \Delta H = 92 kJ/mol

    \Delta S = 2.38 kJ/mol

    Formula used to calculate the value of \Delta G is as follows.

    \Delta G = \Delta H - T\Delta S

    Substitute the values into above formula as follows.

    \Delta G = \Delta H - T\Delta S\\= 92 kJ/mol - (292 K \times 2.38 kJ/mol K)\\= 92 kJ/mol - 694.96 kJ/mol\\= - 602.96 kJ/mol

    Thus, we can conclude that the value of \Delta G is -602.96 kJ/mol at 292 k for a reaction in which \Delta H = 92 kj/mol and \Delta S = 2.38 kj/mol K.

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