What is the total kinetic energy of a 0.15 kg hockey puck sliding at 0.5 m/s and rotating about its center at 8.4 rad/s

Question

What is the total kinetic energy of a 0.15 kg hockey puck sliding at 0.5 m/s and rotating about its center at 8.4 rad/s

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Latifah 7 months 2021-07-12T12:01:17+00:00 1 Answers 6 views 0

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    2021-07-12T12:03:16+00:00

    Answer:

    K=0.023J

    Explanation:

    From the question we are told that:

    Mass m=0.15

    Velocity v=0.5m/s

    Angular Velocity \omega=8.4rad/s

    Generally the equation for Kinetic Energy is mathematically given by

    K=\frac{1}{2}M(v^2+\frac{1}{2}R^2\omega^2)

    K=\frac{1}{2}0.15(0.5^2+\frac{1}{2}(0.038)^2.(8.4rad/s^2))

    K=0.023J

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