what is the slope of the line perpendicular to the line through the points (-1,6) and (3,-4)

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what is the slope of the line perpendicular to the line through the points (-1,6) and (3,-4)

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Linh Đan 6 months 2021-07-30T07:51:39+00:00 2 Answers 5 views 0

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  1. hongcuc2
    0
    2021-07-30T07:53:04+00:00
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    Answer:

    The slope of the line perpendicular to the line through the points (-1,6) and (3,-4) is -5/2.

    Step-by-step explanation:

    We have to find the slope of the line perpendicular to the line through the points (-1,6) and (3,-4).

    using the formula;-

    m = (y²-y¹) / (x²-x¹)

    Where,

    • m = slope
    • ( y² – y¹) = ( -4 -6 )
    • ( x² – x¹) = ( 3 – 1)

    plug the value and simplify.

    m = ( (-4 ) – 6)/(3 – (- 1)

    m = – 10 / 4

    m = – 5/2

    Hence, The slope of the line perpendicular to the line through the points (-1,6) and (3,-4) is -5/2.

  2. ThanhThu
    0
    2021-07-30T07:53:09+00:00
    Reply

    Answer:

    The slope of the perpendicular line is 2/5.

    Step-by-step explanation:

    We want to find the slope of the line that is perpendicular to the line that passes through the points (-1, 6) and (3, -4).

    Recall that the slopes of perpendicular lines are negative reciprocals of each other.

    Find the slope of the original line:

    \displaystyle m=\frac{\Delta y}{\Delta x}=\frac{(-4)-(6)}{(3)-(-1)}=\frac{-10}{4}=-\frac{5}{2}

    The slope of the perpendicular line will be its negative reciprocal.

    Thus, the slope of the perpendicular line is 2/5.

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