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## What is the slope of a line perpendicular to the line whose equation is 6x+3y=-63

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What is the slope of a line perpendicular to the line whose equation is 6x+3y=-63

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Mathematics
5 months
2021-08-15T07:51:03+00:00
2021-08-15T07:51:03+00:00 2 Answers
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## Answers ( )

Answer:y=x/2−63

Step-by-step explanation: 6x+3y=-63 3y=6x-63= y=2/x-63Answer:The slope of a line perpendicular to the line whose equation is 6x+3y=-63 will be: 1/2

Step-by-step explanation:We know that the slope intercept-form of the line equation is

where m is the slope and b is the y-intercept

Given the equation

simplifying the equation to write in the slope-intercept form

Thus, the slope = -2

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line, so

The slope of the perpendicular line will be:

Therefore, the slope of a line perpendicular to the line whose equation is 6x+3y=-63 will be: 1/2