What is the slope of a line perpendicular to the line whose equation is 6x+3y=-63

Question

What is the slope of a line perpendicular to the line whose equation is 6x+3y=-63

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3 months 2021-08-15T07:51:03+00:00 2 Answers 3 views 0

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    0
    2021-08-15T07:52:08+00:00

    Answer:

    y=x/2−63

    Step-by-step explanation:  6x+3y=-63     3y=6x-63= y=2/x-63  

    0
    2021-08-15T07:52:36+00:00

    Answer:

    The slope of a line perpendicular to the line whose equation is 6x+3y=-63 will be: 1/2

    Step-by-step explanation:

    We know that the slope intercept-form of the line equation is

    y=mx+b

    where m is the slope and b is the y-intercept

    Given the equation

    6x+3y=-63

    simplifying the equation to write in the slope-intercept form

    y=-2x-21

    Thus, the slope = -2

    As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line, so

    The slope of the perpendicular line will be:

    \frac{-1}{-2}=\frac{1}{2}

    Therefore, the slope of a line perpendicular to the line whose equation is 6x+3y=-63 will be: 1/2

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )