What is the pressure of a 0.108 mol sample of helium gas at a temperature of 293 K if its volume is 0.505 L?

Question

What is the pressure of a 0.108 mol sample of helium gas at a temperature of 293 K if its volume is 0.505 L?

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Thu Thủy 3 years 2021-07-31T04:29:59+00:00 1 Answers 17 views 0

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  1. diemkieu
    0
    2021-07-31T04:31:28+00:00
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    Answer:

    P = 5.14 atm

    Explanation:

    Given that,

    Pressure of the gas, P = 0.108 mol

    Temperature, T = 293 K

    Volume, V = 0.505 L

    We need to find the pressure of the gas. We know that, according to ideal gas equation,

    PV = nRT

    Where

    P is pressure and R is gas constant

    P=\dfrac{nRT}{V}\\\\P=\dfrac{0.108 \times 0.0821\times 293}{0.505}\\\\P=5.14\ atm

    So, the pressure of the gas is equal to 5.14 atm.

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