What is the net force acting on a falling 1-kg ball if it encounters 2 n of air resistance?

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What is the net force acting on a falling 1-kg ball if it encounters 2 n of air resistance?

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Tryphena 4 years 2021-07-27T03:15:38+00:00 1 Answers 79 views 0

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  1. diemkieu
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    2021-07-27T03:16:40+00:00
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    Answer:

    Net Force= -7.8N

    Explanation:

    fist start by solving the weight of the ball, this means the force pushing the ball down and the mass of the ball combined. we know that the force acting on the ball is gravity. the force of gravity is equivalent to 9.8m/s^2

    weight formula w=mg. w= weight m= mass g= gravity

    w=1kg(9.8m/^2)

    w=9.8kg.m/s^2

    w=9.8N

    Simply add the two forces together to get the net force. The weight 9.8N is negative since it is directed downwards, while the air resistance 2N is positive since it is directed upwards.

    Fnet= -9.8N+2N

    Fnet= -7.8N

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )