What is the molarity of a solution prepared by dissolving 10.0 grams of NaOH in enough water to make a solution with a total volume of 2.40

Question

What is the molarity of a solution prepared by dissolving 10.0 grams of NaOH in enough water to make a solution with a total volume of 2.40 liters?

O0.104 M NaOH
O0.201 M NaOH
O0.361 M NaOH
O0.412 M NaOH

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bonexptip 1 year 2021-08-02T06:13:28+00:00 1 Answers 14 views 0

Answers ( )

    0
    2021-08-02T06:14:28+00:00

    Solution :

    Molecular mass of NaOH is 23 g/mol .

    So, number of moles of NaOH is given by :

    [tex]n = \dfrac{10}{40}\ mole[/tex]

    Now, we know molarity is given by :

    [tex]Molarity = \dfrac{Number \ of \ moles\ of \ salute}{Volume ( in \ Liter ) }[/tex]

    [tex]M = \dfrac{10}{40\times 2.4} \ M\\\\M = 0.104 \ M[/tex]

    Hence, this is the required solution.

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