## What is the molarity of a solution prepared by dissolving 10.0 grams of NaOH in enough water to make a solution with a total volume of 2.40

Question

What is the molarity of a solution prepared by dissolving 10.0 grams of NaOH in enough water to make a solution with a total volume of 2.40 liters?

O0.104 M NaOH
O0.201 M NaOH
O0.361 M NaOH
O0.412 M NaOH

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1 year 2021-08-02T06:13:28+00:00 1 Answers 14 views 0

1. Solution :

Molecular mass of NaOH is 23 g/mol .

So, number of moles of NaOH is given by :

$$n = \dfrac{10}{40}\ mole$$

Now, we know molarity is given by :

$$Molarity = \dfrac{Number \ of \ moles\ of \ salute}{Volume ( in \ Liter ) }$$

$$M = \dfrac{10}{40\times 2.4} \ M\\\\M = 0.104 \ M$$

Hence, this is the required solution.