What is the molarity of 125 mL of a 8.25 M NaCl solution that has been diluted to 750. mL? a) 11 400 M b) 0.00138 M c) 1380 M

Question

What is the molarity of 125 mL of a 8.25 M NaCl solution that has been diluted to 750. mL?
a) 11 400 M
b) 0.00138 M
c) 1380 M
d) 0.0202 M
e) 1.38 M​

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Orla Orla 5 months 2021-08-13T09:30:09+00:00 1 Answers 9 views 0

Answers ( )

    0
    2021-08-13T09:31:27+00:00

    Answer:

    1.375 M

    Explanation:

    Using the formula as follows;

    C1V1 = C2V2

    Where;

    C1 = initial concentration/molarity (M)

    V1 = initial volume (L)

    C2 = final concentration/molarity (M)

    V2 = final volume (L)

    According to the information in this question;

    C1 = 8.25 M

    C2 = ?

    V1 = 125 mL = 125/1000 = 0.125L

    V2 = 750 mL = 750/1000 = 0.750L

    Using C1V1 = C2V2

    8.25 × 0.125 = C2 × 0.750

    1.03125 = 0.750C2

    C2 = 1.03125 ÷ 0.750

    C2 = 1.375 M

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