What is the magnetic force on a particle that has 0.000500 C of charge and is moving at 2.50 10m/s to the right through a magnetic fie

Question

What is the magnetic force on a particle that has 0.000500 C of charge and is moving at
2.50 10m/s to the right through a magnetic field that is 4.20 T and pointing away from
you? Specify both magnitude and direction in your answer.

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Diễm Kiều 5 months 2021-08-14T05:42:59+00:00 1 Answers 2 views 0

Answers ( )

    0
    2021-08-14T05:44:20+00:00

    Answer:

    1.) F = 5.3×10^-3 N

    2.) Positive y – direction

    Explanation:

    The parameters given are:

    Charge q = 0.0005C

    Velocity V = 2.5010 m/s

    Magnetic field B = 4.2 T

    Magnetic force F = BVqsinØ

    F = BVq

    since Ø = 90 degree

    Substitute all the parameters into the formula

    F = 4.2 × 2.5010 × 0.0005

    Therefore, the magnetic force on a particle is F = 5.3 × 10^-3 N

    2.) According to Fleming’s left hand rule, the direction of the magnetic force will be perpendicular to the magnetic field which moving upward of the screen.

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