What is the initial value of h(t)= -9.8t2+48t+50?

Question

What is the initial value of h(t)= -9.8t2+48t+50?

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Jezebel 6 months 2021-08-09T14:35:43+00:00 1 Answers 4 views 0

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    0
    2021-08-09T14:36:45+00:00

    Answer:

    The height h of an object after t seconds is

    h=-16t^2+48t+210h=−16t

    2

    +48t+210

    The height of a neighboring 50-foot tall building is modeled by the equation h=50.

    The time (t) when the object will be at the same height as the building is found to be t = –2 and t = 5.

    To find:

    The statement which describes the validity of these solutions.

    Solution:

    We have,

    h=-16t^2+48t+210h=−16t

    2

    +48t+210

    Here, t is the time in seconds.

    For t=-2,

    h=-16(2)^2+48(-2)+210h=−16(2)

    2

    +48(−2)+210

    h=-64-96+210h=−64−96+210

    h=50h=50

    For t=5,

    h=-16(5)^2+48(5)+210h=−16(5)

    2

    +48(5)+210

    h=-400+240+210h=−400+240+210

    h=50h=50

    So, the value of h is 50 at t=-2 and t=5.

    We know that time is always positive so it cannot be negative value. It means t=-2 is not possible.

    The solution t = 5 is the only valid solution to this system since time cannot be negative.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )