What is the heat of a reaction, in joules, with a total reaction mixture volume of 61.2 mL if the reaction causes a temperature change of 4.

Question

What is the heat of a reaction, in joules, with a total reaction mixture volume of 61.2 mL if the reaction causes a temperature change of 4.6 oC in a calorimeter

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2 months 2021-07-23T12:50:50+00:00 1 Answers 1 views 0

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    2021-07-23T12:52:00+00:00

    Answer:

    1178J is the heat of the reaction

    Explanation:

    Assume that the reaction mixture has a density of 1.00 g/mL and a specific heat of 4.184 J/g-oC. The calorimeter has a heat capacity of 10.0 J/oC

    The heat of a reaction follows the equation:

    Q = m*S*ΔT

    Where Q is the heat of the reaction,

    m is the mass:

    61.2mL * (1.00g/mL) = 61.2g

    S is specific heat = 4.184J/g°C

    ΔT = 4.6°C

    Replacing:

    Q = 61.2g*4.184J/g°C*4.6°C

    Q = 1178J is the heat of the reaction

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