## what is the force on a 1000 kilogram -elevator that is falling freely under the accerleration of gravity only (9.8m/s2)?

Question

what is the force on a 1000 kilogram -elevator that is falling freely under the accerleration of gravity only (9.8m/s2)?

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1 year 2021-08-22T05:15:49+00:00 1 Answers 126 views 0

$$W = 9800 \ \rm N.$$

Explanation:

Given data:

Mass, $$m = 1000 \ kg$$

Acceleration due to gravity, $$g = 9.8 \ m/s^{2}$$

Here, the elevator is in free-fall. The force experienced by the elevator would be equal to its weight.

Thus,

$$W = mg$$

$$W = 1000 \ kg \times 9.80 \ m/s^{2}$$

$$W = 9800 \ \rm N.$$