what is the force on a 1000 kilogram -elevator that is falling freely under the accerleration of gravity only (9.8m/s2)?

Question

what is the force on a 1000 kilogram -elevator that is falling freely under the accerleration of gravity only (9.8m/s2)?

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Phúc Điền 5 months 2021-08-22T05:15:49+00:00 1 Answers 19 views 0

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    2021-08-22T05:17:30+00:00

    Answer:

    W = 9800 \ \rm N.

    Explanation:

    Given data:

    Mass, m = 1000 \ kg

    Acceleration due to gravity, g = 9.8 \ m/s^{2}

    Here, the elevator is in free-fall. The force experienced by the elevator would be equal to its weight.

    Thus,

    W = mg

    W = 1000 \ kg  \times 9.80 \ m/s^{2}

    W = 9800 \ \rm N.

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