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## What is the force exerted by a catcher’s glove on a 0.15 kg baseball moving at 35 m/s that is stopped in 0.02 sec?

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## Answers ( )

Answer: 262.5N

Explanation:

Given that:

Force exerted by a catcher’s glove (F) = ?

Mass of baseball (m) = 0.15 kg

Speed (s) = 35 m/s

Time (t) = 0.02 sec

The force exerted is obtained by dividing the momentum by time.

i.e Force = momentum/time

(since momentum is equal to the product of mass and speed)

i.e F= mv/t

F = (0.15 kg x 35 m/s)/0.02 sec

F = 5.25kgm/s / 0.02 sec

F = 262.5N

Thus, the force exerted by a catcher’s glove is 262.5 newton