What is the force exerted by a catcher’s glove on a 0.15 kg baseball moving at 35 m/s that is stopped in 0.02 sec?

Question

What is the force exerted by a catcher’s glove on a 0.15 kg baseball moving at 35 m/s that is stopped in 0.02 sec?

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Sigridomena 2 months 2021-07-31T21:19:19+00:00 1 Answers 0 views 0

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    2021-07-31T21:20:41+00:00

    Answer: 262.5N

    Explanation:

    Given that:

    Force exerted by a catcher’s glove (F) = ?

    Mass of baseball (m) = 0.15 kg

    Speed (s) = 35 m/s

    Time (t) = 0.02 sec

    The force exerted is obtained by dividing the momentum by time.

    i.e Force = momentum/time

    (since momentum is equal to the product of mass and speed)

    i.e F= mv/t

    F = (0.15 kg x 35 m/s)/0.02 sec

    F = 5.25kgm/s / 0.02 sec

    F = 262.5N

    Thus, the force exerted by a catcher’s glove is 262.5 newton

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