What is the force between two negatively charged objects if q1 = 2.5×10^-6 C, q2 = 4.3×10-6 C and the distance between the charges is 0.04m

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What is the force between two negatively charged objects if q1 = 2.5×10^-6 C, q2 = 4.3×10-6 C and the distance between the charges is 0.04m

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Kim Cúc 4 years 2021-08-03T17:24:44+00:00 1 Answers 13 views 0

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  1. King
    0
    2021-08-03T17:26:04+00:00
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    The force between the charges is 60.47N

    Explanation:

    Given:

    Charge, q₁ = 2.5 X 10⁻⁶ C

                  q₂ = 4.3 X 10⁻⁶ C

    Distance, r = 0.04m

    Force, F = ?

    According to Coulomb’s law:

    F = k\frac{q_1q_2}{r^2}

    where,

    k = Coulomb’s constant

    and the value of k is 9 X 10⁹ Nm²/C²

    On substituting the value we get:

    F = 9 X 10^9X\frac{2.5 X 10^-^6 X 4.3 X 10^-^6}{(0.04)^2} \\\\F = 60.47N

    Therefore, the force between the charges is 60.47N

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )