What is the final velocity of a 1400 kg drag racer that’s engine applies 910000 N of Force for 120m

Question

What is the final velocity of a 1400 kg drag racer that’s engine applies 910000 N of Force for 120m

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Ngọc Hoa 3 years 2021-07-29T19:19:57+00:00 1 Answers 41 views 0

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    2021-07-29T19:20:59+00:00

    Answer:

    468,000,000 m/s

    Explanation:

    According to newtons first law of motion;

    Force = mass * acceleration

    F = ma

    where a = v-u/t

    v is the final velocity

    u is the initial velocity

    t is the time taken

    F = m(v-u/t)

    Ft = m(v-u)

    Given parameters;

    F = 910,000N

    t = 120m = 120 *60 = 7200secs

    m = 1400kg

    u = 0m/s

    Required parameter

    Final velocity v

    Substituting the given parameters into the formula to get v;

    Ft = m(v-u)

    910,000 * 72000 = 1400(v-0)

    910,000 * 72000  = 1400v

    v = (910,000 * 72000)/1400

    v = 910,000 * 720/14

    v = 910,000 * 60

    v = 468,000,000 m/s

    Hence the final velocity of the drag racer is 468,000,000 m/s

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