What is the equation of the circle with center (2,-5) that passes through the point (-2,10). (x-2) ^2 + (y+5)^2=25 (x+2) ^

Question

What is the equation of the circle with center (2,-5) that passes through the point (-2,10).

(x-2) ^2 + (y+5)^2=25
(x+2) ^2 +(y-5)^2=241
(x-2)^2 +(y-5)^2=241
(x+2)^2 + (y-5)^2=25

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Nem 1 year 2021-09-02T14:31:39+00:00 1 Answers 0 views 0

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    2021-09-02T14:33:26+00:00

    Answer:

    b is the answer

    Step-by-step explanation:

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )