What is the equation of the circle with center (2,-5) that passes through the point (-2,10).

(x-2) ^2 + (y+5)^2=25
(x+2) ^2 +(y-5)^2=241
(x-2)^2 +(y-5)^2=241
(x+2)^2 + (y-5)^2=25

Question

What is the equation of the circle with center (2,-5) that passes through the point (-2,10).   (x-2) ^2 + (y+5)^2=25  (x+2) ^2 +(y-5)^2=241  (x-2)^2 +(y-5)^2=241  (x+2)^2 + (y-5)^2=25

ngockhue · Answer

Answer:   b is the answer   Step-by-step explanation:

What is the equation of the circle with center (2,-5) that passes through the point (-2,10). (x-2) ^2 + (y+5)^2=25 (x+2) ^

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