What is the equation of a circle with radius 4 and center (0,8)?

Question

What is the equation of a circle with radius 4 and center (0,8)?

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Phúc Điền 6 months 2021-09-03T21:56:49+00:00 1 Answers 0 views 0

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    2021-09-03T21:58:37+00:00

    The equation of circle with the center at (h,k) is:

      \large \boxed{ {(x - h)}^{2}  +  {(y - k)}^{2}  =  {r}^{2} }

    r stands for radius. Therefore r^2 = diameter or 2×radius.

    The question has already given the information we need, which are:

    • radius = 4
    • the center at (0,8)

    Since the center is (h,k) – therefore the center is at h = 0 and k = 8 making it (h,k) = (0,8).

    Substitute the values in the equation:

     \large{ {(x - 0)}^{2}  +  {(y - 8)}^{2}  =  {4}^{2} }

    Simplify to the simplest form

     \large \boxed{ {x}^{2}  +  {(y - 8)}^{2}  = 16}   \:  \:  \:  \: \huge{ \green{\checkmark}}

    Answer

    • The equation of a circle is x^2+(y8)^2 = 16

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