What is the equation for the reaction between ethanoic acid and butanol in the presence of H2SO4?

Question

What is the equation for the reaction between ethanoic acid and butanol in the presence of H2SO4?

in progress 0
Thiên Thanh 2 months 2021-07-30T07:19:26+00:00 1 Answers 2 views 0

Answers ( )

    0
    2021-07-30T07:21:17+00:00

    Answer:

    CH_3COOH+CH_3CH_2CH_2CH_2OH\rightarrow CH_3COOCH_2CH_2CH_2CH_3+H_2O

    Explanation:

    Hello there!

    In this case, according to the given information, it turns out possible for us to realize this is a question about esterification, process whereby a carboxylic acid and an alcohol react to produce water an an ester, we can set it up as shown below:

    CH_3COOH+CH_3CH_2CH_2CH_2OH

    For the reaction between ethanoic acid and butanol; and therefore, the products side is:

    CH_3COOCH_2CH_2CH_2CH_3+H_2O

    It means that the overall equation is:

    CH_3COOH+CH_3CH_2CH_2CH_2OH\rightarrow CH_3COOCH_2CH_2CH_2CH_3+H_2O

    And the ester product is butyl ethanoate.

    Regards!

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )