What is the domain of the function f(x) =x+1/ X^2-6x+8?

Question

What is the domain of the function f(x) =x+1/
X^2-6x+8?

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bonexptip 2 months 2021-07-23T21:29:30+00:00 1 Answers 3 views 0

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    2021-07-23T21:31:04+00:00

    Answer:

    The domain of the function is all real values of x, except x = 4 and x = 2

    Step-by-step explanation:

    We are given the following function:

    f(x) = \frac{x+1}{x^2-6x+8}

    It’s a fraction, so the domain is all the real values except those in which the denominator is 0.

    Denominator:

    Quadratic equation with a = 1, b = -6, c = 8

    Using bhaskara, the denominator is 0 for these following values of x:

    \Delta = (-6)^2 - 4(1)(8) = 36-32 = 4

    x_{1} = \frac{-(-6) + \sqrt{4}}{2} = 4

    x_{2} = \frac{-(-6) - \sqrt{4}}{2} = 2

    The domain of the function is all real values of x, except x = 4 and x = 2

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )