what is the distance between J(5.4,-3.2) and K(4,-1.2)

Question

what is the distance between J(5.4,-3.2) and K(4,-1.2)

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Nick 6 months 2021-08-17T07:18:24+00:00 1 Answers 6 views 0

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    0
    2021-08-17T07:19:48+00:00

    Answer:

    The answer is

    2.44 units

    Step-by-step explanation:

    The distance between two points can be found by using the formula

    d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  }  \\

    where

    (x1 , y1) and (x2 , y2) are the points

    From the question the points are

    J(5.4,-3.2) and K(4,-1.2)

    The distance between them is

     |JK|   =  \sqrt{ ({5.4 - 4})^{2}  +  ({ - 3.2 + 1.2})^{2} }  \\  =  \sqrt{( {1.4})^{2} +  ({ - 2})^{2}  }  \\  =  \sqrt{1.96 + 4}  \\  =  \sqrt{5.96}  \:  \:  \:  \:  \:  \:  \:  \:  \\  = 2.44131112

    We have the final answer as

    2.44 units

    Hope this helps you

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )