What is the direction of the force exerted on this particle by a magnetic field with magnitude 2.00 TT in the +z+z direction? Express your a

Question

What is the direction of the force exerted on this particle by a magnetic field with magnitude 2.00 TT in the +z+z direction? Express your answer in degrees measured counterclockwise from the +y+y axis.

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Khang Minh 6 months 2021-08-11T00:21:57+00:00 1 Answers 2 views 0

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    2021-08-11T00:23:26+00:00

    Answer:

    145 degree

    Explanation:

    We are given that

    Magnetic field=B=2 T

    Charge on particle,q=-1.75\times 10^{-8} C

    Velocity, v=44.5 km/s

    Angle,\theta=55^{\circ}

    We have to find the direction of the force  exerted on this particle by magnetic field with magnitude 2 T in the z direction.

    Component of velocity along x- axis

    v_x=vcos\theta=44.5 cos55=25.53 km/s

    Along y- axis

    v_y=-44.5sin55=-36.45km/s

    \theta=tan^{-1}(\frac{-36.45}{25.53})

    \theta=tan^{-1}(-1.4277)=-55^{\circ}=180-55=145^{\circ}

    Hence, the direction of force =145 degree

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )