What is the de Broglie wavelength of a bullet of mass 0.030 kg traveling at 540 m/s? Planck’s Constant is 6.63 × 10−34 J⋅s. 4.1

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Question

What is the de Broglie wavelength of a bullet of mass 0.030 kg traveling at 540 m/s? Planck’s Constant is 6.63 × 10−34 J⋅s.

4.1 × 10−35 m
3.5 × 10−35 m
2.2 × 10−34 m
1.7 × 10−34 m

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Physics Hải Đăng 4 years 2021-07-23T09:16:22+00:00 2021-07-23T09:16:22+00:00 1 Answers 38 views 0

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Captcha* Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )

Answer*

thaiduong · Answer 1 · 2021-07-23T09:18:10+00:00

Answer:

I believe the answer is 4.1 * 10^-35 m

Explanation:

I worked out the problem using the equation for this kind of wavelength.

Since I don’t have the special keybind for it, ? will be the wavelength.

? = h/p

In this case, h = Planck’s constant, which is 6.63 * 10^-34 J*s.

P = momentum, which is mass * velocity.

M (mass) = 0.030 kg.

V (velocity) = 540 m/s.

0.030 * 540 = 16.2.

P = 16.2

? = h/p

? = (6.63 * 10^-34) / 16.2.

? = 4.0925 * 10^-35.

? = 4.1 * 10^-35.

The wavelength is 4.1 * 10^-35 m.