# What is the charge on an object that has 1.09×10^13 excess electrons?

Question

What is the charge on an object that has 1.09×10^13 excess electrons?

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1 year 2021-09-04T12:48:56+00:00 1 Answers 10 views 0

$$-1.74\cdot 10^{-6} C$$

Explanation:

The electron is the particle that rotates around the nucleus of the atom; it has a negative electric charge equal to :

$$e=-1.6\cdot 10^{-19}C$$

which is known as fundamental charge.

For an object containing N excess electrons, the total charge of the object is

$$Q=Ne$$

In this problem, the number of excess electrons in the object is:

$$N=1.09\cdot 10^{13}$$

Therefore, by plugging it the numbers, we can find the value of Q, the total charge of the object:

$$Q=(1.09\cdot 10^{13})(-1.6\cdot 10^{-19})=-1.74\cdot 10^{-6} C$$