What is the charge on an object that has 1.09×10^13 excess electrons?

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What is the charge on an object that has 1.09×10^13 excess electrons?

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Nho 1 year 2021-09-04T12:48:56+00:00 1 Answers 10 views 0

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    2021-09-04T12:50:28+00:00

    Answer:

    [tex]-1.74\cdot 10^{-6} C[/tex]

    Explanation:

    The electron is the particle that rotates around the nucleus of the atom; it has a negative electric charge equal to :

    [tex]e=-1.6\cdot 10^{-19}C[/tex]

    which is known as fundamental charge.

    For an object containing N excess electrons, the total charge of the object is

    [tex]Q=Ne[/tex]

    In this problem, the number of excess electrons in the object is:

    [tex]N=1.09\cdot 10^{13}[/tex]

    Therefore, by plugging it the numbers, we can find the value of Q, the total charge of the object:

    [tex]Q=(1.09\cdot 10^{13})(-1.6\cdot 10^{-19})=-1.74\cdot 10^{-6} C[/tex]

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