What is the binding energy of 1 mole of 23 Pu if the mass defect is 0.001896 kg/mol?

Question

What is the binding energy of 1 mole of 23 Pu if the mass defect is 0.001896 kg/mol?

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Thanh Thu 3 months 2021-08-13T20:01:42+00:00 1 Answers 5 views 0

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    2021-08-13T20:03:13+00:00

    Answer:

    1.7 * 10^14 J

    Explanation:

    Recall that binding energy = Δmc^2

    Δm= mass defect

    c = speed of light

    Given that;

    Δm = 0.001896 kg/mol/1 mol = 0.001896 kg

    c=3 * 10^8 m/s

    Binding energy = 0.001896 kg (3 * 10^8 m/s)^2

    Binding energy = 1.7 * 10^14 J

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