What is the amount of moles of NaOH, if the solution molarity is .33 M NaOH in 0.75 L solution

Question

What is the amount of moles of NaOH, if the solution molarity is .33 M NaOH in 0.75 L solution

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Yến Oanh 2 months 2021-08-28T08:01:57+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-28T08:03:11+00:00

    Answer:

    The amount of moles of NaOH is 0.0495

    Explanation:

    Molarity is a measure of concentration that is defined as the number of moles of solute that are dissolved in a given volume.

    In symbolic form molarity  is presented as:

    Molarity=\frac{number of moles of solute}{volume}

    Molarity is expressed in units \frac{moles}{liter}.

    In this case:

    • Molarity= 0.33 M
    • Number of moles of solute= ?
    • Volume= 0.75 L

    Replacing in the definition of molarity:

    0.33 M=\frac{number of moles of solute}{0.75 L}

    number of moles of solute= 0.33 M* 0.75 L

    number of moles of solute= 0.0495 moles

    The amount of moles of NaOH is 0.0495

    0
    2021-08-28T08:03:38+00:00

    Answer:

    0.248 moles of NaOH

    Explanation:

    Concept of Molarity is mol/L

    [x] = 1 M

    1 mol of x contained in 1 L of solution. We write molar concentrations between []

    M = mol/L then M . L = mol

    Our solution is NaOH

    0.33 M . 0.75L = mol

    This solution contains 0.248 moles of NaOH

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