What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q3

What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q3

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  1. This question is incomplete, the complete question is;

    Coulomb’s law for the magnitude of the force F between two particles with charges Q and Q’ separated by a distance d is

    |FI = |QQ’I / d²

    where K = 1/4π∈0, and

    ∈0 = 8.854 × 10⁻¹² C²/(N.m²) is the permittivity of free space.

    Consider two point charges located on the x-axis:

    one charge, q₁ = -18.5 nC, is located at

    x₁ = -1.715m; the charge q₂ = 30.5 nC, is at the origin ( x₂=0 )

    What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q₃ = 51.0 nC placed between q₁ and q₂ at x₃ = -1.085 m ?

    Answer: (Fnet3)x = -3.3287 × 10⁻⁵ N

    Explanation:

    Given that;

    Q₁ = -18.5 nC       Q₃ = 51 nC        Q₂ = 30.5 nC

    x₁ = – 1.715m         x₃ = – 1.085m     x₂ = 0

    Now

    x – component of Net force on charge Q₃ is

    (Fnet3)x = -K|Q₁I|Q₃I / r₁3² – -K|Q₂I|Q₃I / r₂3²

    (Fnet3)x = -(9×10⁹)(51×10⁻⁹) [ 18.5 / ((-1.085 + 1.715)²) + (30.5 / (-1.085)² ] × 10⁻⁹

    (Fnet3)x = -3.3287 × 10⁻⁵ N

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