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What fraction of 5 MeV α particles will be scattered through angles greater than 4.5° from a gold foil (Z = 79, density = 19.3 g/cm3) of thi
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Answers ( )
Answer:
The fraction of particles is
Explanation:
Given :
Alpha particle atomic no.
Gold foil atomic number
Thickness
m
Density

Kinetic energy of alpha particle
V
Scattered angle
4.5°
Fraction of incident particle scattered at angle
is,
Where
number density of particle, 
For calculating value of
Where
,
( Mass number of gold foil )
Put the all value in above equation,
Therefore, the fraction of particles is