What force is needed to pull one microscope slide over another at a speed of 1.00 cm/s, if there is a 0.500-mm-thick layer of 20oC water (η

Question

What force is needed to pull one microscope slide over another at a speed of 1.00 cm/s, if there is a 0.500-mm-thick layer of 20oC water (η = 1.002 mPa∙s) between them and the contact area is 8.00 cm2?

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Khang Minh 6 months 2021-07-27T14:51:02+00:00 1 Answers 32 views 0

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    2021-07-27T14:52:11+00:00

    Answer:

    The force required to pull one microscope is 1.6 \times 10^{-5} N

    Explanation:

    Given:

    Area A = 8 \times 10^{-4} m^{2}

    \eta = 1.002 \times 10^{-3} Pa.s

    Thickness dy = 0.50 \times 10^{-3} m

    Speed dv = 1 \times 10^{-2} \frac{m}{s}

    The force needed to pull one microscope is given by,

        F = A\eta \frac{dv}{dy}

        F = 8 \times 10^{-4} \times 1.002 \times 10^{-3} (\frac{1 \times 10^{-2} }{0.50 \times 10^{-3} } )

        F = 1.6 \times 10^{-5} N

    Therefore, the force required to pull one microscope is 1.6 \times 10^{-5} N

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