What are the zeros of the quadratic function f(x) = 2×2 + 16x – 9? O x=-4- 를 and x = -4+ 7 2 를 O x

Question

What are the zeros of the quadratic function f(x) = 2×2 + 16x – 9?
O x=-4-

and x = -4+
7
2

O x=-4-
25
2
and x = -4+
25
V2
21
O x=-4-
LU
and x = -4 +
21
V2

41
O x=-4-
41
and x = -4 +
V 2

in progress 0
3 months 2021-08-22T11:49:06+00:00 1 Answers 1 views 0

Answers ( )

    0
    2021-08-22T11:50:45+00:00

    Answer:

    \mathrm{X\:Intercepts}:\:\left(\frac{-8+\sqrt{82}}{2},\:0\right),\:\left(-\frac{8+\sqrt{82}}{2},\:0\right)

    Step-by-step explanation:

    f\left(x\right)\:=\:2x^2\:+\:16x\:-\:9

    – Given

    \mathrm{X\:Intercepts}:\:\left(\frac{-8+\sqrt{82}}{2},\:0\right),\:\left(-\frac{8+\sqrt{82}}{2},\:0\right)

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )