what are the horizontal and vertical components of a vector that is 25units long with an angle of 130 degrees​

Question

what are the horizontal and vertical components of a vector that is 25units long with an angle of 130 degrees​

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Orla Orla 4 years 2021-07-26T00:34:38+00:00 1 Answers 12 views 0

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    2021-07-26T00:35:48+00:00

    Answer:

    The horizontal component of the vector is approximately -16.07

    The vertical component of the vector is approximately 19.15

    Explanation:

    A vector quantity is a quantity that posses both magnitude and direction specifications

    The magnitude of the given vector, R = 25 units

    The direction of the vector, θ = 130°

    Therefore the location of the vector, starting from the origin of the Cartesian plane, is in the second quadrant having an angle of 180° – 130° = 50° to the horizontal

    Given that the x-coordinate  is negative in the second quadrant, we have;

    The horizontal component of the vector, Rₓ = The x-coordinate of the vector = R×cos(θ)

    ∴ The horizontal component of the vector, Rₓ = 25 × cos(130°) = -25 × cos(50°) ≈ -16.07

    The horizontal component of the vector, Rₓ ≈ -16.07

    The vertical component of the vector, R_y = The y-coordinate of the vector = R×sin(θ)

    ∴ The vertical component of the vector, R_y = 25 × sin(130°) ≈ 19.15

    The vertical component of the vector, R_y ≈ 19.15

    The vector can be resolved as R = -16.07·i + 19.15·j

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