What are the center and radius of the circle described by the equation x2 + y2 + 6x + 10y +18 = 0?​

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What are the center and radius of the circle described by the equation x2 + y2 + 6x + 10y +18 = 0?​

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Lệ Thu 2 weeks 2021-08-31T23:37:40+00:00 1 Answers 0 views 0

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    2021-08-31T23:39:18+00:00

    This equation is in what’s called general from. To convert to standard form (the form needed to graph: (x-h)^2+(y-k)^2), you would need to first put the x’s next to each other any the y’s next to each other, also put the 18 on the other side.

    1. “x^2+6x+y^2+10y=-18

    2. Complete the square: (b/2)*2
    (x^2+6x+9)+(y^2+10y+25)=-18

    (x+3)^2+(y+5)^2=-18

    Now you have a form where you can tell the center and the radius.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )