We have seen that the heart produces a magnetic field, and that this can be used to diagnose problems with the heart. The magnetic field of

Question

We have seen that the heart produces a magnetic field, and that this can be used to diagnose problems with the heart. The magnetic field of the heart is a dipole field that is produced by a loop current in the outer layers of the heart. Suppose the field at the center of the heart is 90 pT (a pT is 10−12T ) and that the heart has a diameter of approximately 12 cm. What current circulates around the heart to produce this field?

in progress 0
MichaelMet 3 years 2021-09-03T08:28:52+00:00 1 Answers 0 views 0

Answers ( )

  1. minhkhue
    0
    2021-09-03T08:30:10+00:00
    Reply

    Thus the current flowing is 8.8 x 10⁻⁵ A

    Explanation:

    The field at the center of circular current can be calculated by

    B = \frac{\mu _0 I}{r}

    here μ₀ is permeability constant and is equal to 4π x 10⁻⁷

    I is the current in circular path and r is the radius of circle

    Thus I =\frac{90x10^-^1^2x12x10^-^2}{4\pi x 10^-^7 } = 8.8 x 10⁻⁵ A

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )