Vincent dissolves 6.5 g of bromic acid, HBrO3, to prepare 600.0 mL of solution. Calculate the concentration of the acid Vincent produced.

Question

Vincent dissolves 6.5 g of bromic acid, HBrO3, to prepare 600.0 mL of solution. Calculate the concentration of the acid Vincent produced.

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Thiên Hương 3 days 2021-07-18T23:28:33+00:00 1 Answers 0 views 0

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    2021-07-18T23:30:30+00:00

    Answer: The concentration of the acid Vincent produced is 0.083 M.

    Explanation:

    Given: Mass = 6.5 g

    Volume = 600.0 mL (1 mL = 0.001 L) = 0.6 L

    Moles is the mass of substance divided by its molar mass. So, moles of bromic acid (molar mass = 128.91 g/mol) are calculated as follows.

    Moles = \frac{mass}{molar mass}\\= \frac{6.5 g}{128.91 g/mol}\\= 0.05 mol

    Molarity is the number of moles of a substance present in liter of a solution.

    Therefore, molarity (concentration) of the given solution is calculated as follows.

    Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.05 mol}{0.6 L}\\= 0.083 M

    Thus, we can conclude that the concentration of the acid Vincent produced is 0.083 M.

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