Vector A, with magnitude 28.0 units, points in the positive y-direction. Vector A + B has a magnitude of 19.0 units and points in the −y-dir

Question

Vector A, with magnitude 28.0 units, points in the positive y-direction. Vector A + B has a magnitude of 19.0 units and points in the −y-direction. What is the magnitude of B?

in progress 0
Thiên Hương 6 months 2021-08-21T06:56:42+00:00 1 Answers 10 views 0

Answers ( )

    0
    2021-08-21T06:58:24+00:00

    Answer:

    |B|  = 47.0 units

    Explanation:

    The sum of two vectors (A) and (B) gives another vector (A + B). i.e

    (A + B) = (A) + (B)       —————-(i)

    From the question;

    Vector A = 28.0 units in the positive y-direction. This means that the value of the x-component is zero and the value of the y-component is +28

    In unit vector notation vector A is given as;

    A = 0i + 28.0j

    Vector A + B = 19.0 units in the negative y-direction. This means that the value of the x-component is zero and the value of the y-component is -19.0

    In unit vector notation, vector A + B is given as;

    A + B = 0i – 19.0j

    To get the magnitude of vector B, make B the subject of the formula in equation (i) as follows;

    (B) = (A + B) – (A)            —————— (ii)

    Substitute the values of the vectors (A) and (A + B) into equation (ii) as follows;

    (B) = (0i – 19.0j) – (0i + 28.0j)

    (B) = – 19.0j – 28.0j

    (B) = – 47.0j

    The magnitude of B, |B|, is therefore;

    |B| = |-47.0|

    |B| = 47.0 units

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )